Set of illustrations of Dave Schultz in various wrestling poses measured with overall height

Dave Schultz was an American wrestler and a 7-time world and Olympic Gold medalist. He won 10 Senior Wrestling National titles over the span of 19 years at 3 different weight divisions. Dave Schultz was an assistant coach at the University of Oklahoma, Stanford University, and the University of Wisconsin-Madison. In addition to coaching college teams, he also coached teams privately. Dave Schultz was tragically murdered by John Eleuthère du Pont in 1996 at the age of 36. After his death his wife founded the Dave Schultz Wrestling Club which trained and sponsored Wrestling athletes until its closing in 2005.

Collection of outline illustrations of Dave Schultz in wrestling poses

Dave Schultz had a height of 5’8” (1.73 m) and wrestled at a weight of 163 lb (74 kg).

How tall was Dave Schultz?
Dave Schultz was 5 foot 8 inches (1.73 m) tall.

Details

*Under Development*

Height:
5’8” | 1.73 m
Width:
Depth:
Length:
:
:
Weight:
163 lb | 74 kg
Area:
:

Nationality: United States

Years Active: 1980-1995

Death: January 26, 1996

:
:
Birthday:
June 6, 1959

Properties

Drawings include:
Dave Schultz standing, stance, wrestling

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Wrestling is a dueling combat sport where two opponents spar in attempt to pin down each other down through strength and agility. Wrestling has been considered a sport for thousands of years, and is even included in Egyptian hieroglyphs, Greek mythology, and the Old Testament of the Bible.

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